Question

26. Two point charges of 10 uC and 20 uC are separated by 0.1 m in air. The potential energy of the system is
A) 1 . 8 J
(B) 2.4 J
(C) 18 J
(D) 24 J
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Answer 1

Answer:

18 J

Step-by-step explanation:

U=k.q₁.q₂ / r

U = 9*10⁹*10*10⁻⁶*20*10⁻⁶ / 0.1

U = 9 * 10⁹ * 10⁻¹² * 200 * 10

U = 18000 * 10⁻³

U = 18 J.

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