26. Use factor theorem to prove that (x+a) is a factor of (x" +a") for any odd
positive integer n.
answer please.
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Step-by-step explanation:
Hey mates here is your ans
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Correction in question it is (x^n+a^n)
Let p(x) = x^n + a^n , where n is odd positive integer.
Take (x+a)= 0
=> x = -a
Consider:
p(-a) = (-a) ^n + (a) ^n
= -a^n + a^n
= 0
Since, n is odd.
By Factor theorem,
(x+a) is a factor of p(x) when n is odd positive integer.
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Answer:
0 is your answer
Since it is odd
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