Question

26. Weight of 1 L gas is 2 g then find out its V.D. and molecular mass​

Answer 1

Heya,

At N.T.P , volume of 1 mole of gas = 22.4 L

Here, weight of 1 L = 2g

Thus, weight of 22.4 L = 22.4 × 2 = 44.8 gram.

Hence, weight of 1 mole of the gas = 44.8 gram

Thus, molecular mass = 44.8 gram.

and , vapour density = molecular mass/2 = 44.8/2 = 22.4

Regards

Kshitij