Question

26. What is the value of k, if the value of D, for the equations 3x+y=1 and 2x — ky=3 is 7? (A) 22 (B) – 22 (C) 11 (D) – 11​

Answer 1

Step-by-step explanation:

Answer c is correct .Can any one solve this problem with explanation.

Answer 2

Answer:

-3 is the required value of k.

Step-by-step explanation:

Explanation:

Given,  value of D id 7 and the equations are

3x+y=1  ..........(i)

 2x-ky =3 ........(ii)

Where D represent determinant of the given equations.

Step1:

Therefore  we have

3x+y = 1 and 2x-ky = 3

Now find the determinant of this given equations

∴$\left[\begin{array}{ccc}x&y\\3&1\\2&-k\end{array}\right]$ ⇒-3k -2 .

Now we have given in the question that D is 7

Therefore , -3k - 2 = 7

⇒ -3k = 9

⇒k = $\frac{9}{-3} = -3$

Final answer :

Hence , the value of k is -3  which is not given in the options .