26. What is the value of k, if the value of Dy for the equations
3x +y=1 and 2x – ky=3 is 7?
Answers
Answered by
1
Step-by-step explanation:
2x−ky+3=0
3x+2y−1=0
These equations are of the form
a
1
x+b
1
y+c
1
=0,a
2
x+b
2
y+c
2
=0
where a
1
=2,b
1
=−k,c
1
=3, and a
2
=3,b
2
=2,c
2
=−1
Now, for the given pair to have no solution,
a
2
a
1
=
b
2
b
1
=
c
2
c
1
3
2
=
2
−k
=
−1
3
3
2
=−
2
k
and
2
−k
=
−1
3
k=−
3
4
and k
=6
Therefore, k=−
3
4
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