Question

26. What will be the output after execution of the
following instructions?
MOV A, #00H
ANL A, #55H
O a) OOH
Ob) FFH
O c) 55H
O 66H​

Answer 1

Answer:

c 55H

Explanation:

because #00H +#55H = 55H

Answer 2

Option(A) is correct.

Concept:

The ANL instruction does a bitwise logical AND between the provided byte or bit operands and puts the result in the destination operand.

Program:

AND operation between $00H$ and $55H$.

Solution:

ANL is a bitwise AND operation.

$A = 00H$

AND operation between $00H$ and $55H$ is

$0000 \quad 0000= 00H\\\\0101 \quad 0101 = 55H$

______________

$0000 \quad 0000 = 00H$

Hence, the output of the program is $00H$. Option (A) is correct.

Hence, the output of the program is $00H$. Option (B) is incorrect.

Hence, the output of the program is $00H$. Option (C) is incorrect.

Hence, the output of the program is $00H$. Option (D) is incorrect.