Question

26 Z cube of 32 z square minus 18 / 13 z square of 4 Z - 3​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The simplified expression to the given expression is $\frac{26z^3(32z^2-18)}{13z(4z^2-3)}=4z(4z+3)$

Step-by-step explanation:

Given expression is $\frac{26z^3(32z^2-18)}{13z(4z^2-3)}$

To simplify the given expression :

• $\frac{26z^3(32z^2-18)}{13z^2(4z-3)}$
• $=\frac{2z^3.z^{-2}(32z^2-18)}{4z-3}$ ( by using the identity  $\frac{1}{a^m}+a^{-m}$ )
• $=\frac{2z^{3-2}(32z^2-18)}{4z-3}$ ( by using the identity  $a^m.a^{-n}=a^{m-n}$ )
• $=\frac{2z^1(32z^2-18)}{4z-3}$
• $=\frac{2z(32z^2-18)}{4z-3}$
• $=\frac{2z(2)(16z^2-9)}{4z-3}$
• $=\frac{4z(16z^2-9)}{4z-3}$

• $=\frac{4z(4^2z^2-3^2)}{4z-3}$  
• $=\frac{4z((4z)^2-3^2)}{4z-3}$ ( by using the identity  $a^m.b^m=(ab)^m$ )
• $=\frac{4z(4z-3)(4z+3)}{4z-3}$ ( by using the identity  $(a^2-b^2)=(a+b)(a-b)$ )

• $=4z(4z+3)$ ( simplifying the terms )

Therefore the simplified expression is 4z(4z+3)

Therefore $\frac{26z^3(32z^2-18)}{13z(4z^2-3)}=4z(4z+3)$