Question

262 solids of right cylinder kal safe are 49 cm 35 cm high and their base diameter are 16 cm 14 cm respectively both are melted and malt malted into a single cylinder 56 cm high find its diameter

Answer 1

According to question

Radius of first cylinder   R1 = 16/2 = 8 Cm
Height of first cylinder     H1 = 49 Cm

So Volume     V1 = pi R1^2 H1
                            = pi * 64 * 49

Similarly
 Radius of second cylinder    R2 = 14/2 = 7 Cm
Also  Height                           H2 = 35 Cm

So  Volume     V2 = pi R2^2 H2
                              = pi * 49 * 35

When Moulded    Total volume    V = V1 + V2
                                                    V = pi [ 64 * 49 + 49 * 35 ]

Height of New cylinder   H = 56 Cm

Let radius be R

So      V = pi R^2 H
          Pi [ 64 * 49 + 49 * 35 ] = pi R^2 * 56
             R = 9.30 Cm
Thus Diameter = 18.60 Cm