Question

[264.5°C]
3. At a given temperature the pressure of a gas reduces to 75% of its initial
value and the volume
increases by 40% of its initial value. Find this Temperature
if the initial temperature was -10 C
[]​

Answer 1

Given: Initial temperature= -10°C, at a given temperature the pressure of gas reduces to 75% of its initial value, the volume increases by 40% of its initial value.

To find: Temperature of the gas

Solution: According to the ideal gas equation we know that:

PV= nRT

where P is the pressure of the gas, V is the volume of the gas, T is the temperature of the gas, n is the number of moles of the gas

since the number of moles is constant. Therefore, we can say that

P1V1/T1= P2V2/T2

The initial temperature is -10°C that is 283K

Also, pressure is reduced and volume is increased

Putting the values in the equation we will get

P1V1/283= 0.75P1× 1.40V1/T2

1/283= (0.75×1.40)/T2

T2 = 276. 15K

Therefore, the temperature of the gas will be 3.15°C.

Answer 2

Answer:

3.15°C

Explanation:

Given: Initial temperature= -10°C, at a given temperature the pressure of gas reduces to 75% of its initial value, the volume increases by 40% of its initial value. Therefore, the temperature of the gas will be 3. 15°C.