264m² canvas is required to build a conical tent. If the slant height of the cone is 12m, find it's vertical height
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area of canvas = CSA of cone
264 = πrl
22/7*r*12 = 264 (°.° π=22/7 and l = 12 given)
264*7/22*12 = r
r = 7 m
l square = r square + h square
h square = l square - r square
h = √ l square - r square
h = √ 12 square - 7 square
h = √ 144 - 49
h = √ 95
h = 9.746 (approx.)
264 = πrl
22/7*r*12 = 264 (°.° π=22/7 and l = 12 given)
264*7/22*12 = r
r = 7 m
l square = r square + h square
h square = l square - r square
h = √ l square - r square
h = √ 12 square - 7 square
h = √ 144 - 49
h = √ 95
h = 9.746 (approx.)
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