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An object is dropped from
height guim What is
the time
taken to reach
the ground and velocity
ground?
Answers
Answer:
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11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
A ball is released from the...
PHYSICS
A ball is released from the top of a tower of height h metres. It takes T seconds to reach the ground. What is the position of the ball in T/3 seconds?
A
h/9 metres from the ground
B
7h/9m from the ground
C
8h/9 metres from the ground
D
17h/18m from the ground
EASY
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CALCULATOR
Enter the know values to find unknown
Acceleration
Distance
Final Velocity
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
the acceleration of the ball will be g. Initial velocity will be 0.
in T sec. body travels h mts.
by applying equations of motion we get
s=ut+(1/2)gT
2
h=(1/2)gT
2
------[1]
in T/3 sec
h
1
=(1/2)gT
2
=(1/2)g(
3
T
)
2
=(1/2)g(
9
T
2
) -------[2]
from
[1] and [2] we get h
1
=
9
h
distance from point of release.
therefore distance from ground is h−
9
h
=
9
8h
Answer:
It takes to dropped down is time taken 3hour