Question

26z3(32z2-18) ÷13z2(4z-3)

Answer 1

Simplify

Step-by-step explanation:

Given that:

$\frac{26z^3(32z^2-18)}{13z^2(4z-3)}$

dividing value:

$\frac{2z(32z^2-18)}{(4z-3)}$

Taking the common value "2' .

$\frac{2z\cdot 2(16z^2-9)}{(4z-3)}$

$\frac{4z(16z^2-9)}{(4z-3)}$

$\frac{4z(4z)^2-(3)^2}{(4z-3)}$

apply formula:  $(a^2-b^2) = (a+b)(a-b)$

$\frac{4z(4z+3)(4z-3)}{(4z-3)}$

$4z(4z+3) \ or \ (16z^2+12z)$

Learn more:

• Simplify: https://brainly.in/question/4226386