(27/125)^1/3×[(3/2)^-2÷(2/5)^3]-4(3/7)^0
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Step-by-step explanation:
Given (27/125)^1/3×[(3/2)^-2÷(2/5)^3]-4(3/7)^0
- Given (27/125)^1/3×[(3/2)^-2÷(2/5)^3]-4(3/7)^0
- We can write this as
- We know that a^0 = 1 (anything raised to power 0 is 1
- (3^3 / 5^3)^1/3 x [(2/3)^2 / (2/5)^3 ] – 4(1)
- 3/5 x [4/9 / 8 / 125] – 4
- 3/5 x 125 / 18 – 4
- 25 / 6 – 4
- 25 – 24 / 6
= 1/6
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