Math, asked by ishitadma9609, 9 months ago

(27)^2x-1=(243)^3, then find the value of 5^2x-4

Answers

Answered by neeraj6125
3

Answer:

(27)^2x-1=(243)^3

(3)^6x-3=(3)^15

6x-3=15

6x=12

x=2

so according to the question

5^2x-4

=5^2*2-4

=5

therefore answer will be 5

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