(27)^2x-1=(243)^3, then find the value of 5^2x-4
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Answer:
(27)^2x-1=(243)^3
(3)^6x-3=(3)^15
6x-3=15
6x=12
x=2
so according to the question
5^2x-4
=5^2*2-4
=5
therefore answer will be 5
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