Math, asked by nvmishra143, 8 months ago

27
3 (vi) The sum of three
consecutive positive integers
is 51. Find the numbers. तीन
लगातार धनात्मक पूर्णांक का योग 51 है।
संख्याओं का पता लगाएं।

Answers

Answered by bagkakali
0

Answer:

let the numbers are x,x+1,x+2

so,

x+x+1+x+2=51

3x=51-3

3x=48

x=48/3=16

so the numbers are 16,16+1,16+2

the numbers are 16,17,18

Answered by bkpab014
0

Answer:

1st no. = 16

2nd no. = 17

3rd no. = 18

Step-by-step explanation:

Let the first no. be x.

therefore, the 2nd no. = x+1

                 the 3rd no. = x+2

A.T.P,

x+(x+1)+ (x+2) = 51

=> x + x+1 + x+2 = 51

=> 3x + 3 = 51

=> 3x = 51 - 3

=> x = 48/3

=> x = 16

1st no. = 16

2nd no. = 16+1 = 17

3rd no. = 16 + 2 = 18

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