Chemistry, asked by Vuhvffdsdrft, 1 month ago

27.6 g of K2CO3 was treated by a series of reagents so as to convert it into
K2 Zn3 {Fe(CN)6}2
. Calculate the weight of the product.

Answers

Answered by adityasharma1517

1

[mol. wt. of K2CO3 = 138 and mol. wt. of K2 Zn3 [Fe(CN)6]2 = 698]

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