Question

√27+ √75 +√48- √108 if √3 = 1.7​

Answer 1

Answer:

10.2

Step-by-step explanation:

√27+√75+√48-√108

√(3*3*3)+√(3*5*5)+√(3*4*4)-√(2*2*3*3*3)

=3√3+5√3+4√3-6√3

=√3(3+5+4-6)

=√3(6)

=1.7*6

=10.2

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Answer 2

$√27+√75+√48−√108if√3=1.7$

Simplifies to:

$→−18fi+20.78461=1.7$