Question

(27/8)^1=(3/2)^4+x find the value of x​

Answer 1

Answer:

(3/2)^3=(3/2)^4+x

27/8 - 81/16= x

x = -27/16

Answer 2

Explanation:

$( \frac{27}{8} ) {}^{1} = ( \frac{3}{2} ) {}^{4 + x}$

$(( \frac{3}{2} ) {}^{3} ) {}^{1} = ( \frac{3}{2} ) {}^{4 + x}$

$( \frac{3}{2} ) {}^{3} = ( \frac{3}{2} ) {}^{4 + x}$

$( \frac{3}{2} ) {}^{(3 = 4 + x)}$

$( \frac{3}{2} ) {}^{(x = 3 - 4)}$

$( \frac{3}{2} ) {}^{(x = - 1)}$

$( \frac{3}{2} ) {}^{ - 1}$

$( \frac{2}{3} )$

$the \: value \: of \: x \: is \: - 1$