Question

(27)½×(81)⅞ ans. please​

Answer 1

Answer:

SOLUTION:

i) required ratio =\frac{81}{108}=\frac{81\div27}{108\div27}=\frac{3}{4}=3:410881=108÷2781÷27=43=3:4

[HCF of 81 and 108 = 27]

ii) required ratio= \frac{98}{63}=\frac{98\div7}{63\div7}=\frac{14}{9}=14:96398=63÷798÷7=914=14:9

[HCF of 98 and 63=7]

iii) required ratio = =\frac{33}{121}=\frac{33\div11}{121\div11}=\frac{3}{11}=3:11=12133=121÷1133÷11=113=3:11

[HCF of 33 and 121 =11]

iv) required ratio = \frac{30}{45}=\frac{30\div15}{45\div15}=\frac{2}{3}=2:3\4530=45÷1530÷15=32=2:3 

{HCF of 30 and 45= 15]

Answer 2

Answer:

$3 \sqrt{3 } + 9 + 9 {?}^{?} {1 \div 8}^{?}$