Question

27. A bag contains 3 red balls, 2 blue balls and 4 yellow balls. If R, B and Y are elementary events, then prove that P(R) + P(B) + P(Y) = 1.






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Answer 1

Step-by-step explanation:

P(R)=3/9

P(B)=2/9

P(Y)=4/9

P(R)+P(B)+P(Y)=3/9+2/9+4/9=9/9=1

Answer 2

number of red balls=3

number of blue balls=2

number of yellow balls=4

total number of balls=9

probability of red balls p(R)=3/9=1/3

probability of blue balls p(B)=2/9

probability of yellow balls p(y)=4/9

p(R)+p(B)+p(y)=1

1/3+2/9+4/9

3+2+4/9

9/9

1