Question

27. A ball is dropped from the top of a tower of height h and
it travels a distance 15h/64 in the last second. The time of
journey and height of tower is
(1) 4 s, 160 m
(2) 8 s, 320 m
(3) 4 s, 320 m
(4) 8 s, 160 m​

Answer 1

Answer:

option 2 is correct

Explanation:

i am assuming distance travelled in last second as h/64 m.

we know that distance travelled in last second is = u*n + g/2*(2*n - 1)

substitute u =0, g = 10 m/s^2, n=1 sec,

in above equation we get

h/64 = 0 + 10/2*(1)

h =320 m

also

320 = (1/2) *10*t^2

t^2 = 64

t = 8 sec