27. A ball is projected vertically upward from the
ground. The ball is at the same height at t = 3 S
and t = 9 s. The height of ball at t = 5 s is
(g = 10 ms-2)
(1) 180 m
(2) 175 m
(3) 135 m
(4) 200 m
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Answered by
1
Answer:
ans is in the picture. hope you understand
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Answered by
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answer : option (2) 175m
explanation : A ball is projected vertically upwards from the ground with speed u m/s.
then according to formula,
s = ut + 1/2 at²
here, a = -g
so, s = ut - 1/2 gt²
a/c to question,
The ball is at the same height at t = 3 S
and t = 9 s
so, s = u(3) - 1/2g(3)² = 3u - 9g/2 .....(1)
and s = u(9) - 1/2 g(9)² = 9u - 81g/2.....(2)
from equations (1) and (2),
we get, 6u - (81g - 9g)/2 = 0
⇒6u = 72g/2
⇒u = 6g .......(3)
from equation (1), s = 3(6g) - 9g/2
= 27g/2
now height of ball at t = 5s , h = u(5) - 1/2g(5)²
= 6g(5) - 25g/2 [ from equation (3)]
= 30g - 25g/2
= 35g/2
= 35 × 10/2 = 35 × 5 = 175m
hence, option (2) is correct choice.
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