27. A divalent metal has equivalent weight 28. Its atomic weight is:
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Answer:
Equivalent weight =
valency
molecular weight
24=
2
M
w
M
w
=48= Molecular weight of divalent metal X
Moles of X=
48
12
=0.25
X+2HCl→XCl
2
+H
2
0.25 0.50 − −
0.25 0.25
Moles of H
2
produced =0.25 moles
Volume of 0.25 moles H
2
=0.25×22.4=5.6 litres
Explanation:
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