Question

27. A particle is projected from the top of a
tower of height 100 m with a velocity
v = (301 +40)) m/s at time t = 0. The velocity vector
of the particle at t = 9 s will be (take y-axis vertical
and x-axis as horizontal, g = 10 m/s2)
(1) (30î - 10ſ)m/s
(3) (30 – 50ſ)m/s
(2) (30î – 40ſ)m/s
(4) (30i – 30ſ)m/s
​

Answer 1

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