Question

27. A particle moving with a uniform acceleration travels 24 metres and 64 metres in first two successo
of 4 seconds each. Its initial velocity is
(1)
1 m/s
(2) 2 m/s
(3) 5 m/s
(4) 10 m/s
which of​

Answer 1

Answer:

10m/s

Explanation:

a=(Sm-Sn)/m-n

a=(64-24)8-4

a=10m/s^2

Sn=u+a/2(2n-1)

24=u+10/2(2×4-1)

24=u+5(7)

u=10m/s(apx)

Answer 2

Answer:

1 m/s

Explanation:

S1 = u(4) + 0.5a(16)

24 = 4u + 8a

6 = u + 2a

For S2 :

v = u + at = u + a(4)

S2 = (u+4a)(4) + 0.5a(16)

64 = 4u + 16a + 8a

64 = 4u + 24a

16 = u + 6a = (u + 2a) + 4a

16 = 6 + 4a

10 = 4a

a = 10/4 = 2.5 m/s^2

u = 6-2a = 6-2*2.5 = 1