Question

27. A ray of green light enters a liquid from air, as shown in Fig. 4.21. Angle 1 is 45° and angle 2 is 30º.
(a) Find the refractive index of the liquid.
(b) Show in the diagram the path of the ray after it strikes the mirror and re-enters in air. Mark in the diagram the angles wherever necessary.
(c) Redraw the diagram if plane mirror becomes normal to the refracted ray inside the liquid. State the principle used.

Please answer this without any exceptional work for 25 points.​

Answer 1

Given that,

First angle = 45°

Second angle = 30°

A ray of green light enters a liquid from air.

(a). We need to calculate the refractive index of the liquid

Using formula of refractive index

$\mu=\dfrac{\sin\ i}{\sin\ r}$

Put the value into the formula

$\mu=\dfrac{\sin 45}{\sin 30}$

$\mu=1.414$

(b). We shows in the diagram the path of the ray after it strikes the mirror and re-enters in air.

(c). We redraw the diagram if plane mirror becomes normal to the refracted ray inside the liquid. State the principle used

Hence, The refractive index of the liquid is 1.414.

Answer 2

Answer:

the above solution is correct