Question

27. A scooterist sees a bus 1 km ahead of him
moving with a velocity of 10 ms -1. With what
speed the scooterist should move so as to
overtake the bus in 100 s?
a) 10 ms-i b)15 ms c)20 ms-1 d)17 ms1​

Answer 1

Given, distance covered by scooterist = 1 km

We know that 1 km = 1000 m.

So, distance (s) = 1000 m

Also given that, velocity = 10 m/s and time = 100 sec.

We have to find that with what speed the scooterist should move so as to overtake the bus in 100 sec.

Both bus and scooterists are travelling in the same direction.

So,

Relative Velocity (scooterist with respect of bus) = Velocity of scooterist - Velocity of bus

10 = Velocity of scooterist - 10

10 + 10 = Velocity of scooterist

20 = Velocity of scooterist

Option c) 20 m/s

Answer 2

⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀${ \huge \bf{ \mid{ \overline{ \underline{ \pink{QUESTION}}}} \mid}} \longrightarrow</p><p>$

A scooterist sees a bus 1 km ahead of him moving with a velocity of 10 ms -1.With what speed the scooterist should move so as to overtake the bus in 100 s?

_________________________

⠀⠀⠀⠀${ \huge{ \mathbf{ \overbrace{ \underbrace{ \purple{ANSWER}}}}}}$

options:-

a)10m/s , b)15m/s,. c)20m/s ✔️, d)17m/s

_________________________

$\large\underline{ \underline{ \green{ \bold {given}}}} = >$

• distance covered by scooterist =1 km

⠀⠀⠀⠀⠀${ \boxed{ 1km = 1000m}}$

so,

distance that the scooterist covered= 1000m.

• Velocity = 10 m/s
• time =100 seconds

$\large\underline{ \underline{ \green{ \bold{find}}}} = >$

speed of scooterist so that it overtake the bus in 100s.

$\large\underline{ \underline{ \green{ \bold {</strong><strong>Solu</strong><strong>tion</strong><strong>}}}} = >$

The bus and the scooterist both are moved in the same direction.

therefore,

relative velocity =

Velocity of scooterist- velocity of bus.

$10 = velocity \: of \: scoorist - 10 \\ 10 + 10 = velocity \: of \: scoorist \\ \\ \boxed{ \fbox{20 = velocity \: of \: scoorist}}$

option C is correct.