Question

27.
A vernier scale has 10 divisions. It slides over a main scale, whose pitch is 1.0 mm
If the number of divisions on the left hand of zero of the vernier scale on the main
scale is 56 and the 8th vernier scale division coincides with the main scale, calculate
the length in centimetre.


A 5.68 m
B) 5.68 mm
C) 5.68 cm
D) 0.568 mm​

Answer 1

Answer:

C) 5.68 cm

Explanation:

$least \: count \: = \frac{pitch \: of \: main \: scale}{number \: of \: division \: on \: vernier \: scale} \: \: \\ = \frac{1mm}{10} \: \\ = 0.1 \: mm \: \\ \\ length \: = \: main \: scale \: reading \: + \: (nnumber \: of \: vernier \: scale \: coincidence \: \times \: least \: count) \: \: \\ = 56.8mm \: \\ = 5.68 \: cm$