Question

27. A vessel contains 300 ml of pure syrup. 30
ml is removed and replaced with water. This
process is repeated 3 more times. What is the
concentration of water in the resulting mixture?
1) 120 ml
2) 131.22 ml
3) 103.17 ml
4) 100 ml

Answer 1

Answer:

i think it should be no.2

Step-by-step explanation:

i think no.2 us your answer

Answer 2

The answer is 3) 103.17 ml

Given

• A vessel contains 300 ml of pure syrup.
• 30 ml is removed and replaced with water.
• This process is repeated 3 more times.

To find

The concentration of water in the final mixture

Solution

Number of times this replacement is performed = 4 times

We know that for any process,

Final Concentration of syrup =

The initial concentration of syrup X (1 - replaced/initial)ⁿ

where n = no. of times replacement was performed

Hence the concentration of water = 300 - concentration of syrup

Final Concentration of syrup

=300 X (1 - 30/300)⁴

= 300 X (270/300)⁴

= 300 X  (9/10)⁴

= 300 X 9/10 X 9/10 X 9/10 X 9/10

= 19683/100 ml

= 196.83 ml

Hence concentration of water = 300 ml - 196.83 ml

= 103.17 ml

Hence the answer is 3) 103.17 ml

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