Math, asked by kesavisathiya2006, 1 month ago

27.Calculate the zeroes of the polynomial () = 4
^2 − 12 + 9.​

Answers

Answered by Anonymous
3

Answer:

Let P(x) = 4x2 -12x + 9.

= 4x2 - 6x + 9.

or, p(x) = 2x(2x - 3) -3(2x - 3)

:. 0 = (2x - 3) (2x - 3)

The zeros are 3 / 2, 3 / 2.

:. x = 3 / 2, 3 / 2.

Hence, zeroes of the polynomial are 3 / 2, 3 / 2.

Step-by-step explanation:

hope its helpful

sam

Answered by kanakchapa
0

Step-by-step explanation:

Let P(x) = 4x^2-12x + 9.

= 4x^2 - 6x + 9.

or, p(x) = 2x(2x - 3) -3(2x - 3)

:. 0 = (2x - 3) (2x - 3)

The zeros are 3 / 2, 3 / 2.

:. x = 3 / 2, 3 / 2.

Hence, zeroes of the polynomial are 3 / 2, 3 / 2.

Similar questions