Question

27 Construct a PQR , in which AB =90, LR=800
.
and PQ+QR+PR =9,5 cm​

Answer 1

Answer:

In APQR, QR= 6 cm, PR-PQ=2 cm & ZQ= 60°

Steps of construction:

1. Draw the base QR-6 cm.

At Point Q draw a ray QX making an ZXQR-60°

Here, PR -PQ= 2cm

PR>PQ

The side containing the base angle Q is less than

third side.

2. Cut the line segment QS equal to PR-PQ=2 cm, from the ray QX extended on opposite side of base QR.

3. Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

4. Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.

Thus APQR is the required Triangle.

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