Question

27 drops of same size are charged at 220 volt each they collapse to form a bigger drop calculate the potential of bigger drop​

Answer 1

Answer:1980

Explanation:let r and R be radius ,v=220V

And v be the potential

Q and q be the charge on each small sphere and bigger sphere.

Q=27q

4/3 pie R^3=4/3 pie r^3

R^3 =(3r)^3

R=3r

Potential of bigger drop =1/4pieE. Q/R

1/4pieE. - 27q/3r

9×(1/4pieE. ×q/r)

9×220

1980

E.》》》epsilon not