Question

27. Find n if X0 = 0.75825, x = 0.759
and h = 0.00005.​

Answer 1

Answer:

15

Step-by-step explanation:

Answer 2

SOLUTION

GIVEN

$\sf x_0 = 0.75825 \: , \: x = 0.759 \:, \: h = 0.00005$

TO DETERMINE

The value of n

FORMULA TO BE IMPLEMENTED

We are aware of the formula that

$\sf x = x_0 + n h$

EVALUATION

Here it is given that

$\sf x_0 = 0.75825 \: , \: x = 0.759 \:, \: h = 0.00005$

Now we have

$\sf x = x_0 + nh$

$\sf \implies 0.759 = 0.75825 + (n \times 0.00005)$

$\sf \implies (n \times 0.00005) =0.759 - 0.75825$

$\sf \implies (n \times 0.00005) =0.00075$

$\sf \implies n = \dfrac{0.00075}{0.00005}$

$\sf \implies n = 15$

FINAL ANSWER

Hence the required value of n = 15

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