Question

27. Find the equation of the line passing through the point (1, 4) and intersecting the linex – 2y – 11 = 0 on the y-axis​

Answer 1

Step-by-step explanation:

Given, line x−2y−11=0 passes through y - axis and point (1,4)

So, putting x=0 in the line equation we get the y -intercept

0−2y−11=0

y=2−11

The co-ordinates are (0,2−11)

Now, the slope of the line joining the points (1,4) and (0,2−11) is given by

m=x2−x1y2−y1

=(0−1)(2−11)

=219

Thus,the line equation will be

y−y1=m(x−x1)

y+211=219(x−0)

2y+11=19x

⇒19x−2y−11=0