27. Find the length of the wire
required to fence 2 rounds of a
rectangular park of length 25 m and
breadth 10 m.
50 m
140 m
100 cm
Answers
Answer:
The length of wire required to fence the park twice = 140m.
SOLUTION
Length of the rectangular park = 25m.
Breadth of the rectangular park = 10m.
Perimeter of a rectangle = 2(l + b) , Where l is the length and b is the breadth of the rectangle.
Here,
l = 25m.
b = 10m.
Perimeter of the rectangular park = 2(l + b)
⇒ Perimeter of the rectangular park = 2(25 + 10)
⇒ Perimeter of the rectangular park = 2 × 35
⇒ Perimeter of the rectangular park = 70m.
Length of wire required to fence the park twice = 2 × 70 = 140m.
Answer:
140 m
Step-by-step explanation:
Question-
Find the length of the wire required to fence 2 rounds of a rectangular park of length 25 m and
breadth 10 m.
ㅤ
Given-
- Length= 25 m
- Breadth= 10m
ㅤ
To Find-
- Perimeter.
- Length of wire required to fence with 2 rounds of the rectangular park.
ㅤ
Solution-
- Perimeter - to find the perimeter of the rectangular park, we'll use the below boxed formula and find the perimeter by calculating the measurements further.
ㅤㅤㅤㅤㅤ2(10+25)
ㅤㅤㅤㅤㅤ= 2×35
ㅤㅤㅤㅤㅤ= 70 m
ㅤ
- Length of wire required to fence with 2 rounds of the rectangular park- as we know that the perimeter of the rectangular park is the length of wire required to cover it once, and now to find find the length required for 2 rounds, we'll multiply the perimeter of the rectangular park by 2.
ㅤㅤㅤㅤㅤ2(perimeter)
ㅤㅤㅤㅤㅤ=2×70
ㅤㅤㅤㅤㅤ= 140 m
ㅤ
So, required length-