27. Find the perimeter of the triangle whose vertices are (-2,1),(4,6) and (6,3).
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Answer:
19.226 units
Step-by-step explanation:
The length of a line in a coordinate system is simply√((X-x)^2+(Y-y)^2).
Length of line1=√(6^2+5^2)=√61
Length of line2=√(2^2+3^2)=√13
Legth of line3=√(8^2+2^2)=√68
Perimeter of ∆=Sum of all sides.
Perimeter=√(68)+√(61)+√(13)~=19.226
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