Question

27. Find the perimeter of the triangle whose vertices are (-2,1),(4,6) and (6,3).​

Answer 1

Answer:

19.226 units

Step-by-step explanation:

The length of a line in a coordinate system is simply√((X-x)^2+(Y-y)^2).

Length of line1=√(6^2+5^2)=√61

Length of line2=√(2^2+3^2)=√13

Legth of line3=√(8^2+2^2)=√68

Perimeter of ∆=Sum of all sides.

Perimeter=√(68)+√(61)+√(13)~=19.226