Question

27. For eccentricity in hyperbola (e)
which relation is correct?
(1 Point)
e < 1
e = 1
e > 1
e = 0​

Answer 1

Answer:

Equation of hyperbola is

a

2

x

2

−

b

2

y

2

=1

∵b

2

=a

2

(e

2

−1)

⇒e

2

=1+

a

2

b

2

=

a

2

a

2

+b

2

Equation of conjugate hyperbola is

a

2

x

2

−

b

2

y

2

=−1

⇒

b

2

y

2

−

a

2

x

2

=1

∴e

′

2

=1+

b

2

a

2

=

b

2

a

2

+b

2

Now,

e

2

1

+

e

′

2

1

=

a

2

+b

2

a

2

+b

2

=1

Answer 2

The correct relation for eccentricity in hyperbola (e) is :

Explanation:

• Eccentricity can be defined as a parameter associated with every conic section.
• It is a measure of how much the conic section deviates from being circular.  
• When (e < 1    Ellipse), (e = 1     Parabola), (e > 1     Hyperbola), (e = ∞   straight line), (e = 0   Circle).
• e < 1 is the answer.