Question

27, Forin the pair of linear equations in the following problems and find their solution graphically.
Two years ago, a father was five times as old as his son. Two years later, his
will be 8 more than three times the age of the son.​

Answer 1

Answer:

According to question, we have

(x−1)=5(y−2)

⇒x−5y=−8 ...(1)

(x+2)=3(y+2)+8

⇒x−3y=12 ...(2)

Subtracting equation (1) from (2), we get

⇒2y=20⇒y=10

Puting y=10 in equation (1), we get

x−3×10=12⇒x=42

The present ages of father and son are 42 years

and 10 years respectively.