27. From a point on the ground, the angles of elevation of the top and bottom of
a transmission tower fixed at the top of a 20m high building are 60° and 450
respectively. Find the height of the transmission tower.
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Step-by-step explanation:
Let DC be the tower and BC be the building. Then,
∠CAB=45°,∠DAB=60° ,BC=20 m
Let height of the tower, DC=h m.
In right△ABC,
tan45° = BC/AB
1 = 20/AB
AB=20 m
In right △ABD,
tan60° = BD/AB
√3 = h + 20 / 20
h=20(√2 - 1 ) m
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