27. From the top of a building 50 3 M high the angle of depression of a car on
the ground is observed to be 60°. Find the distance of the car from the Foot of
a building.
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2
Answer:
50 m
Step-by-step explanation:
Let QR be the distance of the car from the building.
Now, In △PQR
⇒tan60°=
QR
PQ
=
QR
50
3
⇒
3
=
QR
50
3
⇒QR=50m
∴ The car is at 50m distant from the building.
Hence, the answer is 50m
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