27 g of Al is heated with 49 ml of h2so4 ( specific gr = 2 ) produce h2 gas calculate the volume of h2 gas at ntp and persentage react with h2so4
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2Al+3H
2
SO
4
⟶Al
2
(SO
4
)
3
+3H
2
↑
2 moles of Al reacts with 3 moles of H
2
SO
4
.
i.e. 2×27g reacts with 3×98g H
2
SO
4
.
Mass of H
2
SO
4
present =49×2=98g
∴ Mass of Al reacted =
3
2
×27=18g
∴% Al reacted =
27
18
×100=66.66%
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