27 g of Al will react completely with how much mass of O2, to produce A12O3
Answers
Explanation:
i don't know sorry if you know this answer write in your note books of Al will react completely with how muc27 g of Al will react completely with how much mass of O2, to produce A12O3h mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O327 g of Al will react completely with how much mass of O2, to produce A12O3
The balanced chemical reaction is :-
→ 4Al + 3O2 --→ 2Al2O3
→ Therefore 4mole of Al3 mole of O2
→ So, for 1 mole Al3/4 mole O2 is needed
→ 3/4 × 32 = 24g
ANSWER is → 24g
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