Question

27. How many geometrical isomers are possible for
given compound?
C6H5 -CH=CH-CH=CH-COOH
(1) 3
(2) 4
(3) 2
(4) 1​

Answer 1

Answer:

the answer is 4 . please follow me

Answer 2

Answer:

The correct answer is option 2

Explanation:

• Stereoisomerism can be further divided into configurational isomerism, conformational isomerism, and geometrical isomerism.
• Conformational isomers are interconvertible forms of the same molecule derived from the rotation of the carbon-carbon σ bond.
• Configurational isomers are those stereoisomers that cannot be converted to each other by rotation about the carbon-carbon σ bond.
• The geometrical isomers are non- interconvertible stereoisomers due to the restricted rotation of the carbon-carbon π bond. Since free rotation around the carbon-carbon pi bond is restricted, the molecule exists in two non- interconvertible and different geometries.
• The geometrical isomer in which similar groups are present in the same direction or on the same side of the double bond is known as the cis isomer. The geometrical isomer, in which similar groups are present on the opposite sides of the double bond is known as the trans isomer. Hence, geometrical isomerism is also commonly known as cis-trans isomerism.
• In the given question, the given compound contains two double bonds and the groups at each end are different, i.e., methyl and ethyl groups. Therefore, the total number of geometrical isomers for each double bond will be two. Hence there are 4 geometrical isomers for the given compound.

Thus, the correct answer is 2.