Question

27.
How many moles of caco3 present in 5 litres of 0.3 m solution​

Answer 1

Answer:

Number of moles of solute = 1.5

Explanation:

Volume of solution in litres = 5 l

Molarity = 0.3

therefore ,    

                      $Molarity =\frac{Number of moles of solute}{Volume of solution in litres}$

0.3 = Number of moles of solute / 5

Number of moles of solute = 0.3 * 5

Number of moles of solute = 1.5.

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