27. If a = 1/(3−√11)and b = 1/a, then find a2
– b2
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Step-by-step explanation:
Given ,
AB and CD are two parallel tangents at the point P and Q of a circle with centre O.
To prove - POQ is a diameter of the circle.
Construction - Join OP and OQ and draw .
Proof √ APQ + √ TOP = 90°
Similarly, √ TOQ = 90° + 90° = 180°
Since , POQ is straight line.
Hence , POQ is a diameter of the circle with centre O.
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