Question

27) If p(x)=x2-6x+k
a) Find p(2) ?
b) Find the value of k if x-2 is a factor of p(x)
​

Answer 1

Answer:

a) P(2)=k-8

b) K=8

Step-by-step explanation:

a) p(2)= (2)^2-6(2)+k

p(2)= 4-12+k

p(2)= k-8

b) If x-2 is a factor,

(2)^2-6(2)+k=0

4-12+k=0

k-8=0

k=8

Answer 2

Answer:

a) -8 + k

b) 8

Step-by-step explanation:

a)

$p(x) = x {}^{2} - 6x + k$

$p(2) = 2 {}^{2} - 6 \times 2 + k \\ = 4 - 12 + k \\= - 8 + k \: \: \: \: \\ \\ \:$

b) SINCE x - 2 a factor of p(x)

So, x = 2 .

$p(2) = 2 {}^{2} - 6 \times 2 + k \\ = > 0 \: = 2 {}^{2} - 6 \times 2 + k \\= > 0 = 4 - 12 + k \: \\ = > 0 = - 8 + k \\ = > k \: = 8$