Question

27. If the roots of the quadratic equation x2 +(a+1)x+b=0 are 2 &-3, find a & b.
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Answer 1

sum of roots = -b/a

-1 = -(a+1)

-1 = -a -1

0 = a

Answer 2

Answer:

sum of root=b/a-1= - (a+1)-1 = -a -10 =a

Step-by-step explanation:

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