Question

27. If (x + 1)2 + (y + 2)2 + (z + 3)2 = 0, then the value of x2 + y2 +2+ is (where x, y, zeR) a) 7 b) 6 c) 14 d) 15​

Answer 1

Substitute 3 for x in p(x),

p(3)

=3(3)−2−3

2

=9−2−9

=−2