27. in the given circuit, the internal resistance of the battery equals:
a. 0.5 0.
b. 10
C. 2 0
d. 40
A A
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Explanation:
4ohm and 4ohm are parallel
1/Rp = 1/4 + 1/4
= 1/2
Rp = 2ohm
Now 4ohm and 2ohm are in series
Rs = 4 + 2
= 6ohm
R = 6ohm
V = 14V
V = IR
14 = I x 6
I = 14/6
= 7/3
= 2.5 A
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