Math, asked by Dheeraj7728, 10 months ago

27 ka power minus 2 by 3 into 81 power 5 by 4 divided by 1 by 3 ki power minus 3

Answers

Answered by rsibashankar
0

 {27}^{2 \div 3}  \times  {81}^{5 \div 4}  \div  {1 \div 3}^{ - 3}

=

 {3}^{2} \times  {3}^{5}  \div {3}^{3}

then,

 {3}^{7}  \div  {3}^{3}

 {3}^{7 - 3}

 {3}^{4}

hope its helps you thank you..

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Answered by amitnrw
2

Given  :  27 ka power minus 2 by 3 into 81 power 5 by 4 divided by 1 by 3 ki power minus 3

\dfrac{(27)^{-\frac{2}{3}} (81)^{\frac{5}{4} }}{ (\dfrac{1}{3})^{-3} }

To Find  : Simplify

Solution:

\dfrac{(27)^{-\frac{2}{3}} (81)^{\frac{5}{4} }}{ (\dfrac{1}{3})^{-3} }

(xᵃ)ᵇ = xᵃᵇ

xᵃ = 1/x⁻ᵃ

(a / b)ⁿ = aⁿ/bⁿ

aⁿ . bⁿ  = (ab)ⁿ

xᵃ . xᵇ = xᵃ⁺ᵇ

a⁰ = 1

27  = 3³

81 = 3⁴

\dfrac{(3^3)^{-\frac{2}{3}} (3^4)^{\frac{5}{4} }}{ 3^3 }

\dfrac{(3)^{-2} (3^5)}{ 3^3 }

(3)^{-2+5-3}

3⁰

= 1

\dfrac{(27)^{-\frac{2}{3}} (81)^{\frac{5}{4} }}{ (\dfrac{1}{3})^{-3} }=1

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